TV
A frog is sitting on the ground when he is scared by a big dog. His movement is modeled by
the equation h = -6t2 + 6t where h is the frog's height at any given time, t. How many
seconds until the frog is back on the ground?
2 seconds
1.5 seconds
3 seconds
1 second
0.5 seconds

Step-by-step explanation:

Model of the frog jump is

h = -6t² + 6t

When will the frog be on the ground? The frog will be on the ground at h=0

Therefore,

0 = -6t² + 6t

Divide through by 6

0 = -t² + t

0 = t(-t + 1)

So, t = 0 OR. 0 = -t + 1

So, t = 0. OR. t = 1

So, we should note that, at t = 0, was when he wanted to lift of from the ground... So, t = 0 will be discarded

So, at t = 1 is when the frog is back to the ground.

It is like it starts from the ground at the 0 seconds and get backs to the ground at 1 seconds

I hope this helps!!!

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x