Construct a 95% prediction interval for y given x=-3.5, ^y= 2.097x - .552 and se= .976

95% Confidence interval for y

= (-9.804, -5.979)

Lower limit = -9.804

Upper limit = -5.979

Step-by-step explanation:

^y= 2.097x - 0.552

x = -3.5

Standard error = 0.976

Mathematically,

Confidence Interval = (Mean) ± (Margin of error)

Mean = 2.097x - 0.552 = (2.097×-3.5) - 0.552 = - 7.8915

(note that x=-3.5)

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value for 95% confidence interval = 1.960

Standard Error of the mean = 0.976

95% Confidence Interval = (Mean) ± [(Critical value) × (standard Error of the mean)]

CI = -7.8915 ± (1.960 × 0.976)

CI = -7.8915 ± 1.91296

95% CI = (-9.80446, -5.97854)

95% Confidence interval for y

= (-9.804, -5.979)

Hope this Helps!!!

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step-by-step explanation: