The tempature was very cold, tgen it doubled, then it dropped 10 degrees, and then it increased by 40 degrees. The tempature is now 16 degrees. What was the starting tempature?

Answer

The initial temperature was T = -7 degrees

Step-by-step explanation:

Let the initial temperature be T.

- The tempature was very cold

Temperarure = T

- Then it doubled

Temperature = 2T

- Then it dropped 10 degrees

Temperature = 2T - 10

- And then it increased by 40 degrees.

Temperature = 2T - 10 + 40 = 2T + 30

The tempature is now 16 degrees

Temperature = 16 degrees

2T + 30 = 16

2T = -14

T = -7 degrees

Hope this Helps!!!

The starting temperature was -7 degrees

Step-by-step explanation:

Let's call the inicial temperature by 'X'.

First the temperature doubled, so now it is 2X.

Then, it dropped 10 degrees, so now it is 2X - 10

Then, it increased by 40 degrees, so now it is 2X - 10 + 40 = 2X + 30

Now, the temperature is 16 degrees, so we have that:

2X + 30 = 16

2X = 16 - 30

2X = -14

X = -7

The starting temperature was -7 degrees

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.