Define f(1) in a way that extends f(s)=(s^3-1)/(s^2-1) to be continuous at s=1. show step-by-step solution.

For a function to be continous right hand limit should be equal to left hand limit 
so que means that we have simply find the limit at s tends to 10 
f(s)=[(s-1)(s^2+1s-1)]/[(s-1)(s+1... 

=>f(s)=[s^2+1s+1]/(s+1) 

putting s=1

f(s)=6