An automobile insurance company claims that teenage drivers save on average $490 per year when compared to the same coverage from another company, with a standard deviation of $65 per year. Natalia is a teenager and a customer of this company and her average savings was $470 per year. What is the z-value for Natalia’s savings rounded to the nearest hundredth?
Question 1 options:

a)
The z-value is -0.90.
b)
The z-value is 0.90
c)
The z-value is 0.31.
d)
The z-value is -0.31.

d) The z-value is -0.31

Step-by-step explanation:

-Given that Natalia's saving is $470,  mean claim amount is $490 and the standard deviation is $65

-Let Natalia's savings be X

#The z-value is calculated using the formula:

Hence, Natalia's z-value is -0.31

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.

honestly bro aint no one got time to answer these dumb question just do it p***y

step-by-step explanation: