How many 5-digit numbers are there that are divisible by either 45 or 60 but are not divisible by 90?

2500 numbers

Step-by-step explanation:

Problem;

 Solving for the number of 5-digit numbers divisible either by 45 or 60 but not divisible by 90;

 Let us approach this in a step wise manner;

  5 -digits numbers ranges from 10,000 to 99,999

To solve this problem, let us find the number of digits that are divisible by 45;  

  the first number divisible by 45 within this range is 10035

   the last number divisible by 45 in this range is 99990

    increment is 45

The total number in this range is:

             + 1  =  + 1

                                                      =  2000 numbers

To solve this problem, let us find the number of digits that are divisible by 60;  

  the first number divisible by 60 within this range is 10020

   the last number divisible by  in this range is 99960

    increment is 60

The total number in this range is:

                 + 1  =  + 1  

                                                         =  1500 numbers

To solve this problem, let us find the number of digits that are divisible by 90;  

  the first number divisible by 90 within this range is 10080

   the last number divisible by  in this range is 99990

    increment is 90

The total number in this range is:

          + 1  = + 1

                                                  = 1000 numbers

Now solution:

  Number of 5 digits  = number of 45  + number of 60 - number of 90

                                       = 2000 + 1500  - 1000

                                        = 2500 numbers

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn