In 2014, students in an advanced Statistics course at UC Berkeley conducted an anonymous survey about use of cognition-enhancing drugs among college 1o points males. One survey group of males included members from a fraternity, and the other survey of males group included no fraternity members. The difference between the proportion of fraternity members who have used cognition-enhancing drugs and the proportion of n members who have used cognition-enhancing drugs is equal to o.054. Which one of the following conclusions is true? on-fraternity A. Students who are not fraternity members use cognition-enhancing drugs at higher rates than fraternity members. B. One possibility is that the proportion of fraternity members who have used cognition- enhancing drugs is 0.295 and the proportion of non-fraternity members who have used cognition-enhancing drugs is o.241. C. Students could have discovered that the proportion of fraternity members who have used cognition-enhancing drugs is o.315 and the proportion of non-fraternity members who have used cognition-enhancing drugs is o.369.

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

idek

step-by-step explanation:

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation:

step-by-step explanation:

classify each pair of angles as alternate interior, same-side interior, or corresponding angles.