End of the quarter is soon and I'm dying in quarentine!! Increasing the air temperature inside a hot air balloon makes it lighter than the surrounding air, so the balloon can lift up. The density of hot air is about 0.5kg/m3. less than that of cool air, which means a cubic meter of hot air can lift about 0.25kg. What is the minimum volume of hot air needed to lift a hot air balloon carrying 500kg

Hi there! Hopefully this helps!

The volume of air = 2000 m³

Explanation:

We are given that 1 m³ of hot air can lift a mass of about 0.25 kg.

To find the volume of hot air required to lift a mass of 500 kg, we will use cross-multiplication as follows:

1 m³ > 0.25 kg

?? >500 kg

volume of hot air required = (500*1) / (0.25)

volume of hot air required =  2000 m³

the solution is 12x-6y

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?