Solve the system of equations
x + 3y = 5
-x + 6y = 4

A) x = 1, y = 2
B) x = 2, y = 1
C) x = 1, y = 1
D) x = 0, y = 2

  B) x = 2, y = 1

Step-by-step explanation:

Add the two equations to eliminate the x-variable.

  (x +3y) +(-x +6y) = (5) +(4)

  9y = 9 . . . . . . .simplify

  y = 1 . . . . . . . . divide by 9

You can substitute this value into either equation to find x.

  x + 3(1) = 5

  x = 2 . . . . . . . . subtract 3

The solution is (x, y) = (2, 1).

B) x=2, y=1

Step-by-step explanation:

x+3y=5

-x+6y=4

solve the equation

x=5-3y

-x+6y=4

substitute the value of x into an equation

-1(5-3y)+6y=4

multiply numbers in parenthesis by -1

-5-3y+6y=4

put -5 as positive and add 5 to 4 and put -3y as positive and add to 6y.

9y=9

divide both sides by 9

y=1

substitute the value of y into an equation

x=5-3•1

multiply 3 to 1

x= 5-3

subtract 5 to 3

x=2

x=2

y=1

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -