a quadratic function is defined by f(x)=4x2+3x+2. A linear function is defined by g(x)=mx+1. What value(s) of the slope of the line would make it a tangent to the parabola
Show all steps
Please help!!! will mark brainliest

m = -1, 7

Step-by-step explanation:

4x² + 3x + 2 = mx + 1

4x² + (3 - m)x + 1 = 0

Tangent meets the curve at one point

B²-4AC = 0

(3 - m)² - 4(4)(1) = 0

(3 - m)² = 16

3 - m = 4

m = -1

3 - m = -4

m = 7

8y^50

step-by-step explanation:

umumumumum

im not sure