A simple random sample of 105 analog circuits is obtained at random from an ongoing production process in which 30% of all circuits produced are defective. Let X be a binomial random variable corresponding to the number of defective circuits in the sample. Use the normal approximation to the binomial distribution to compute P ( 26 ≤ X ≤ 36 ) , the probability that between 26 and 36 circuits in the sample are defective. Report your answer to two decimal places of precision.

since we know that the two functions are equal, f (x) = g

(x), therefore when we equate the two equations the result should be similar to

3x = x – 4:

a. f(x) = 3x, g(x) = x – 4

equating the two functions:

3x = x – 4             (correct)

so we now got our answer (a)

8(4)^8=72^feet to say that the total can conclude to 8(4) which as you know would mean 8 x 4. that equals 32w. 32^ could make a 72 answer as well. but your coefficent will remain w so your answer is 72w.

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sorry but i cant draw that

i belive the biggest ratio would be 18: correct me if im wrong