What algebraic expression must be subtracted from the sum of y2 + 5y - 1 and 3y2-2y + 4 to give 2y2 + 7y-2 as the result

The required expression is 2y² - 4y + 5.

Step-by-step explanation:

We have to find the sum of first 2 expressions and then subtracting an expression, let us consider a, to give the third expression. We have to find a.

y² + 5y -1 + 3y² - 2y + 4

We have to group the like terms and doing the addition as,

= y² + 3y² + 5y -2y -1 + 4

= 4y² + 3y + 3

Now we have to subtract an expression a from the above sum to get the third expression.

4y² + 3y + 3 - a = 2y² + 7y - 2

Now we have to group the terms as,

a = 4y² + 3y + 3 - (2y² + 7y - 2)

  = 4y² + 3y + 3 - 2y² - 7y + 2

Rearranging the terms as,

a = 4y² - 2y² + 3y - 7y + 3 + 2

   = 2y² - 4y + 5

So the required expression is 2y² - 4y + 5.

good luck on your studies! : )

david edward.

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.