How much carbon dioxide will you prevent from entering the atmosphere in one year, if you replace a 100-watt light bulb with a CFL bulb that uses 30 watts in a fixture that you have on 8 hours per day? (round to the hundredths place)

280000lb

Step-by-step explanation:

In this question, we shall be calculating the amount of carbon iv oxide prevented from entering the atmosphere.

Generally we know that 1kwh produces 1.37 lbs of Carbon iv oxide in the atmosphere

Now, using a 100 watt light bulb daily for 8 hours, for a year, the amount of Carbon iv oxide produced will be;

100 * 1.37 * 8 * 365 = 40040 lb

Using a 30 watt CFL for 8hrs/ day for a year, we have;

30 * 1.37 * 8 * 365 = 120012 lb

Now calculating the amount of CO2 prevented, we have 40040 - 120012 = 280028 lb = 280000 after rounding up

it 2

step-by-step explanation:

8^1/3=2

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions