The store manager of Price Chopper wants to put two cereal box displays side by side. Each of the displays will be constructed with forty-eight boxes. The bottom layer of each cereal box display is six cereal boxes long. Each cereal box display cannot be higher than ten boxes. What are two possible sets of dimensions for the two cereal box displays when they are placed side by side? How many cereal boxes can the new display hold?

The two possible displays are;

(1) 6 boxes wide by 8 boxes high and

(2) 12 boxes wide and 4 boxes high

The number of cereal box the new display will hold combined is 96 cereal boxes

Step-by-step explanation:

Here we have that the length of the bottom layer = 6 cereal boxes

Maximum height cannot be more than ten boxes high

Number of cereal box per display = 48

Therefore one cereal box display can be 6 boxes wide by 8 boxes high

While if the cereal box dimensions are Length = 2 × Width

Then the second cereal box display can be 12 boxes wide and 4 boxes high

The two possible sets of dimensions are;

(1) 6 boxes wide by 8 boxes high and

(2) 12 boxes wide and 4 boxes high

The first display will hold 48 cereal box displays while the second will hold

12 × 0.5 × 4 × 2 = 48 cereal boxes

The combined number of cereal boxes the new display will hold is 48 + 48 = 96.

452,489 to the nearest thousand is 452,000

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²