Ask Your Teacher Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter μ = 20 (suggested in the article "Dynamic Ride Sharing: Theory and Practice"†). (Round your answer to three decimal places.) (a) What is the probability that the number of drivers will be at most 13? (b) What is the probability that the number of drivers will exceed 25? (c) What is the probability that the number of drivers will be between 13 and 25, inclusive? What is the probability that the number of drivers will be strictly between 13 and 25? (d) What is the probability that the number of drivers will be within 2 standard deviations of the mean value?

a) 0.00613 b) 0.113 c) 0.821, 0.804 d) 0.99997

Step-by-step explanation:

Cumulative Poisson probability=∑(e^-μ) (μ^x) / k!

μ: mean=20

x: max number of successes

k: number of success from 1 to x

e= 2.71828

In this question use poisson distribtuion calculator

a) x≤13

(e^-20) (20^13) / 1! + (e^-20) (20^13) / 2! + + (e^-20) (20^13) / 13!

probability= 0.00613

b) x>25

probability= 1- P(X≤25,20)

                = 0.113

c) probability( 13≤x≤25)= P(X≤25,20)-P(X≤13,20)

                                           0.88728 - 0.06613

                                       = 0.821

probability( 13<x<25)= P(X<25,20)- P(X<13,20)

                                    = 0.84323-0.03901

                                        = 0.804

d) In poisson distribution, variance = mean

So, here x=40

P(X<40) = 0.99997

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: