At a carnival, 700 tickets were sold for a total

amount of $5.500. An adult ticket cost $10

and a children's Icket cost $5. Find the

number of adult tickets (x) and the number of

children's lickets (y) sold.

The adult tickets are 400 and the children tickets are 300.

Step-by-step explanation:

Given:

At a carnival, 700 tickets were sold for a total  amount of $5500. An adult ticket cost $10   and a children's ticket cost $5.

Now, to find the  number of adult tickets and the number of  children's tickets sold.

Let the number of adult tickets be

And let the number of children tickets be

So, the total number of tickets sold:

Now, the total amount of tickets:

Substituting the value of from equation (1):

Subtracting both sides by 3500 we get:

Dividing boths sides by 5 we get:

The number of adult tickets = 400.

Now, substituting the value of in equation (1) we get:

The number of children tickets = 300.

Therefore, the adult tickets are 400 and the children tickets are 300.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

good luck on your studies! : )

david edward.