The area of a circular base of the larger cylinder is 81π. The area of a circular base of the smaller cylinder is 9π.

Make a conjecture about the similar solids. How is the scale factor and the ratio of the surface areas related? Check all that apply.

- The dimensions of the larger cylinder are 3 times the dimensions of the smaller cylinder.
- The surface area of the larger cylinder is 32, or 9, times the surface area of the smaller cylinder.
- If proportional dimensional changes are made to a solid figure, then the surface area will change by the square of the scale factor of similar solids.

A & C

The dimensions of the larger cylinder are 3 times the dimensions of the smaller cylinder.

If proportional dimensional changes are made to a solid figure, then the surface area will change by the square of the scale factor of similar solids.

Step-by-step explanation:

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true