A footbridge is in the shape of an arc of a circle. The bridge is 4.5 ft tall and 25 ft wide. What is the radius of the circle that contains the bridge? Round to the nearest tenth.

Assuming that the 36 feet wide line base is NOT a diameter, make a sketch

let the radius be x

then I see a right-angled triangle where

Step-by-step explanation:

(x-8)^2 + 18^2 = x^2

x^2 - 16x + 64 + 324 = x^2

-16x = -388

x = 24.25

draw a chord AB, your base , = 36

From the centre O draw a line OA , a radius

let the radius be x

so OA = x, the hypotenuse

from the centre draw a perpendicular to AB to hit AB at C

from C to the circle is 8 , so OC = x-8

OCA is a right - angled triangle.

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

answer: sherk

step-by-step explanation:

just give up and watch the best anime ever sherk