Given m∠LON\qquad m \angle LON m∠LON m, angle, L, O, N is a straight angle. m∠LOM=4x+30∘\qquad m \angle LOM = 4x + 30^\circ m∠LOM=4x+30 ∘ m, angle, L, O, M, equals, 4, x, plus, 30, degrees m∠MON=8x+90∘\qquad m \angle MON = 8x + 90^\circ m∠MON=8x+90 ∘ m, angle, M, O, N, equals, 8, x, plus, 90, degrees Find m∠MONm\angle MON m∠MON m, angle, M, O, N : OO O LL L NN N MM M ∘{}^{\circ} ∘ degrees Show Calculator Stuck?Watch a video or use a hint. Report a problem

5x+10 is the correct one

hope this

costs the what? what is the cost of the pants?

step-by-step explanation:

if it is $10, then the price is 14.

take 40% of the cost, and then add the cost.

40% of 10 = 4

4+10 = 14.

chiken

step-by-step explanation:

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.