When a pair of dice are rolled there are 36 different possible outcomes: 1-1, 1-2, ... 6-6. If a pair of dice are rolled 3 times, what is the probability of getting a sum of 5 every time? Round to eight decimal places.

The probability of getting a sum of 5 every time is 0,137174%

Step-by-step explanation:

First we have to get the probability of getting a 5 when we rolled 2 dices.

1+1=2 // 1+2=3 // 1+3=4 // 1+4=5 the rest are higher

2+1=3 // 2+2=4 // 2+3=5  the rest are higher

3+1=4 // 3+2=5  the rest are higher

4+1=5 the rest are higher

The rest of the sum are higher.

So, the P(getting a sum of 5)=4/36=0.11

When two or more events are independent, the probability of all occurring is the product of the probabilities of the individual events. More formally, if events A and B are independent, then the probability of both A and B and C occurring is:

P(A and B and C) = P(A) x P(B)  x P(B)

In this case,

P(A and B and C) =4/36 x 4/36 x4/36

P(A and B and C) =0.00137174

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

me

step-by-step explanation: