The endpoints of directed line segment PQ have coordinates of P(-7,5) and Q(5,3). What are the coordinates of point A, on PQ, that divide PQ into a ratio of 1:3?

Correction

P(-7,-5)

d(-4,-3)

Step-by-step explanation:

-Given the coordinates of PQ as  P(-7,5) and Q(5,3).

-The sum of the ratios is:

Let d be the point that divide's the segment in the ratio 1:3

#The coordinates that divide the segment into a 1:3 ratio therefore has to be from P.

#We determine the length of the x-axis coordinate:

#We determine the length of the y-axis coordinate:

Hence, the coordinates of point d is d(-4,-3)

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.