A survey of several 9 to 11 year olds recorded the following amounts spent on a trip to the mall: $10.31,$17.22,$26.62,$22.84 Construct the 98% confidence interval for the average amount spent by 9 to 11 year olds on a trip to the mall. Assume the population is approximately normal. Step 1 of 4 : Calculate the sample mean for the given sample data. Round your answer to two decimal places.

Step-by-step explanation:

From the information given,

Mean, μ = (10.31 + 17.22 + 26.62 + 22.84)/4 = 19.2475

Standard deviation, σ = √summation(x - mean)/n

Summation(x - mean) = (10.31 - 19.2475)^2+ (17.22 - 19.2475)^2 + (26.62 - 19.2475)^2 + (22.84 - 19.2475)^2 = 151.249475

σ = √(151.249475/4)

σ = 6.15

number of sample, n = 4

The z score for 98% confidence interval is 2.33

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

It becomes

19.2475 ± 2.33 × 6.15/√4

= 19.2475 ± 2.33 × 3.075

= 19.2475 ± 7.16

The lower end of the confidence interval is 19.2475 - 7.16 = 12.09

The upper end of the confidence interval is 19.2475 + 7.16 = 26.41

answer: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

step-by-step explanation: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

a

step-by-step explanation: