A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240.
If we want to provide a 95% confidence interval for the SAT scores, the degrees of freedom for reading the critical values of "t" statistic is:.

Degree of freedom = 63

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 64

Sample mean = 1400

Sample standard deviation = 240

We need to make a 95% confidence interval.

We use the t-statistic for the same.

Degree of freedom:

Degree of freedom  for reading the critical values of t-statistic is

Thus, the degree of freedom is 63.

step-by-step explanation:

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4