Three men and seven women are waiting to be interviewed for jobs. If they are all selected in random order, find the probability that no man will be interviewed until at least two women have been interviewed. The probability is nothing.

1/50

Step-by-step explanation:

Given that:

We need to find the probability that no man will be interviewed until at least two women have been interviewed. So there are two possible probabilities are:

1. One man and two women => P(1 man and 2 women) = 3/10*2/9 = 1/15

2. Three women => P(3 women) = 3/10

Hence, the probability in this situation is: 1/15*3/10 = 1/50