Given three non-collinear points $A$, $B$, and $C$, construct three circles that are pairwise tangent at these points. (In other words, two of the three circles are tangent at $A$, two are tangent at $B$, and two are tangent at $C$.) Are there any cases where such circles do not exist

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.

mx+89b(-98)nb

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )