Two tourists left two towns simultaneously, the distance between which is 38 km, and met in 4 hours. What was the speed of each of the tourists, if the first one covered 2 km more than the second one before they met

= 5 km/hr

= 4.5 km/r

Step-by-step explanation:

Distance of two tourists can be represented by and  

Therefore, the total distance would be

+ =38  ----> (eq1)

->if the first one covered 2 km more than the second

= +2   (substituting this in above equation)

We will have,

( +2)+ =38

2+2=38

2=36

= 36/2

=18

plugging value of in eq(1)

eq(1)=>

 + = 38

 + 18 =38

= 20 km

the distance of each of the tourists

=20km and =18km

As they both traveled for 4 hrs

t=4hr

speed can be defined as distance per unit time i.e

speed 'v' = distance 'd' / time 't'

Let and represent speed of each of the tourists

Therefore,

=  /t => 20/4

= 5 km/hr

=   /t => 18/4

= 4.5 km/r

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40