A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 72 specimens and counts the number of seeds in each. Use her sample results (mean = 56.1, standard deviation = 16.7) to find the 99% confidence interval for the number of seeds for the species. Enter your answer as an open-interval (i. e., parentheses) accurate to one decimal place (because the sample statistics are reported accurate to one decimal place).

99% Confidence interval:   (50.9,61.3)        

Step-by-step explanation:

We are given the following in the question:

Sample mean, = 56.1

Sample size, n = 72

Alpha, α = 0.01

Sample standard deviation, σ = 16.7

Degree of freedom = n - 1 = 71

99% Confidence interval:  

Putting the values, we get,  

step-by-step explanation:

i need to answer questions so i dont know but i think its the first one because it goes up but a consent rate

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew