What is the equation of a line that has a slope of -2/3 and passes through point (-3,-1)?

y = -(2/3)x - 3

To completely find the equation of the line, we have to find b, or the y-intercept. This is where the line intersects the y-axis, or the vertical axis.

To find b, we can substitute y and x with (-3, -1) because we know that this is a point which is satisfied by the equation of the line.y = -(2/3)x + bSubstitute (x, y) with (-3, -1)x --> -3y --> -1-1 = -(2/3)(-3) + b-1 = 2 + bb = -3y = -(2/3)x - 3Check our work. Just plug in the value of (-3, -1), and see if it works!-1 = -(2/3)(-3) - 3-1 = 2 - 3-1 = -1It works!

Letter a i would say