A die is rolled two separate times. What is the probability that the first roll is a 4 and then the second roll is a 2? *

So we know that rolling a fair six-sided die twice would mean the total possible outcomes would be 36, and rolling the 4 on the first roll and a 2 on the second roll would be 2/36 or 1/18

Step-by-step explanation:

(1/6)*(1/6)=(2/36)=(1/18)

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

i really dont know

step-by-step explanation: