The Center for Disease Control and Prevention reports that the rate of Chlamydia infections among American women ages 20-24 is 2791.5 per 100,000.
a) Find the probability that a randomly chosen American women between the ages of 20 and 24 does not have a Chlamydia infection.
b) Find the odds of a Chlamydia infection in the 20 to 24 year old US female population is approximately.

A. 0.972085

B. 0.028717

Step-by-step explanation:

To solve this question, we proceed as follows;

First, we calculate the probability p = 2791.5/100000 = 0.027915

a) probability that a randomly chosen American women between the ages of 20 and 24 does not have a Chlamydia infection = 1-0.027915 = 0.972085

b) odds of a Chlamydia infection in the 20 to 24 year old US female population = number of people with thedisease to the number of people without it in a particular population

= 0.027915 / 0.972085 = 0.028717

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

the answer on ed. is:

c. "the graph of f(x) has exactly two x-intercepts."

hope i could someone! : )