If the life in years of a television set is normally distributed with a mean of 36 years and a standard deviation of 8 years what should be the guarantee period if the company wants less than 3% of the television sets to fail while under warranty

The company should guarantee a lifetime of less than equal to 20.95 years so that less than 3% of the television sets fail while under warranty.    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 36 years

Standard Deviation, σ = 8 years

We are given that the distribution of life of television sets is a bell shaped distribution that is a normal distribution.

Formula:

We have to find the value of x such that the probability is 0.03.

Calculation the value from standard normal z table, we have,  

Thus, the company should guarantee a lifetime of less than or equal to 20.95 years so that less than 3% of the television sets fail while under warranty.

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3