On a certain hot summer's day, 611 people used the public swimming pool. The daily prices are $ 1.75 for children and $ 2.00 for adults. The receipts for admission totaled $ 1143.75 . How many children and how many adults swam at the public pool that day?

298 adults and 313 children

Step-by-step explanation:

In this case we can solve it using a 2x2 system of equations, like this:

let x: children's tickets

let y: adult's tickets

So:

1.75 * x + 2 * y = 1143.75

x + y = 611 => x = 611 - y

Replacing, we are left with that:

1.75 * (611 - y) + 2 * y = 1143.75

1069.25 - 1.75 * y + 2 * y = 1143.75

- 1.75 * y + 2 * y = 1143.75 - 1069.25

0.25 * y = 74.5

y = 74.5 /0.25

y = 298

Now to calculate x:

x = 611-298

x = 313

It means that there were 298 adults and 313 children

7 weeks

step-by-step explanation:

convert each fraction to the least common multiple of 20, so 3/4 = 15/20 & 1/10 = 2/20, then divide 15 by 2 and you get a little over 7, so the food will last 7 weeks.

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol