Solve this problem using the above process. A rectangular field is 4 times as long as it is wide. If the length is decreased by 10 feet and the width is increased by 2 feet, the perimeter will be 80 feet. Find the dimensions of the original field.

original width= 9.6  feet

original length = 38.4  feet

Step-by-step explanation:

Hi, to answer this question we have to apply the formula  

P =2w +2 L

Where:

P=perimeter

W= width

L = length

Since the field is 4 times as long as it is wide

L= 4W

So, if the length is decreased by 10 feet and the width is increased by 2 feet, the perimeter will be 80 feet.

Mathematically speaking

80= 2 (W+2) + 2(L-10)

Simplifying:

80 = 2w+4 +2L-20

Replacing the value of L by 4W

80 = 2W +4 +2(4W)-20

Solving for W:

80=2W +4 +8W-20

80-4+20= 2W+8W

96= 10W

96/10 =W

W= 9.6  feet

Replacing the value of W in the Length equation:

L =4W

L = 4 (9.6)

L = 38.4  feet

answer: h

step-by-step explanation:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!