Which expression is equivalent to (x^2 -8) - (-2x^2+4)?

D) 3x^2 - 12

Step-by-step explanation:

Using PEMDAS;

There is no need to evaluate the part of the equation (x^2 - 8) because is no need to, as it is already in its simplest form.

We must evaluate the part of the equation continuing with, "- (-2x^2+4)," as it is not in its simplest form.

Evaluating "- (-2x^2+4)":

Step 1: Distributing the negative

Once distributing the negative symbol amongst the values within the parenthesis according to PEMDAS, we get "2x^2 - 4" as the product.

Step 2: Consider the rest of the equation to evaluate

Since the part of the equation is still in play here as it is a part of the original equation to be solved, we must evaluate it as a whole to get the final answer.

Thus,

x^2 -8 + 2x^2 - 4 = ___

*we can remove the parenthesis as it has no purpose, since it makes no difference.

Evaluating for the answer, we get,

x^2+2x^2 + (-8 - 4) = 3x^2 - 12

Hence, the answer is D) 3x^2 - 12.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.