Laboratory experiment shows that the life of the average butterfly is normally distributed with a mean of 18.8 days and a standard deviation of 2 days. Find the probability that a butterfly will live between 12.04 and 18.38 days.

41.64% probability that a butterfly will live between 12.04 and 18.38 days.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Find the probability that a butterfly will live between 12.04 and 18.38 days.

This is the pvalue of Z when X = 18.38 subtracted by the pvalue of Z when X = 12.04. So

X = 18.38

has a pvalue of 0.4168

X = 12.04

has a pvalue of 0.0004

0.4168 - 0.0004 = 0.4164

41.64% probability that a butterfly will live between 12.04 and 18.38 days.

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

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