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Mathematics, 14.04.2020 07:25 lin550

On a coordinate plane, a line goes through (negative 1, 1) and (0, negative 3). A point is at (negative 4, negative 3) and (0, negative 3).
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (βˆ’4, βˆ’3)?

y + 3 = βˆ’4(x + 4)
y + 3 = –One-fourth(x + 4)
y + 3 = One-fourth(x + 4)
y + 3 = 4(x + 4)


On a coordinate plane, a line goes through (negative 1, 1) and (0, negative 3). A point is at (negat

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