A weather balloon holds 2,850 cubic meters of helium. The density of helium is 0.1685 kilograms per cubic meter. How many kilograms of helium does the balloon contain? Please round your answer to the nearest whole number. Only enter a numerical value in the answer blank

480

Step-by-step explanation:

Density of a substance is mass per unit volume, Mathematically expressed as

d=m/v

Making m the subject of the formula then

m=dv

Here, d is the density, m is the mass of helium and v is the volume of helium

Given density as 0.1685 kg/m³ and volume as 2850 m³ then jts mass will be equivalent to

Mass=2850m³*0.1685kg/m³=480.225 kg

Rounding off to the nearest whole number, the mass is approximately 480 kg

5

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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