2 Two cars left the city for a suburb, 480 km away, at the same time. The speed of one of the cars was 20 km/hour greater than the speed of the other, and that is why it arrived at the suburb 2 hour earlier than the other car. Find the speeds of both cars.

80 km

60 km

Step-by-step explanation:

Remember that; time = distance/ speed

Assume that the first car is traveling at x km/h

The second is traveling at (x+20) km/h

The distance is given as 480km

The difference in their arrival is 2hrs. Therefore;

480/x – 480/(x+20) = 2

480(x+20) – 480x = 2x(x+20)

480x + 9600 - 480x = 2x² – 40x

2x² - 40x - 9600 = 0

2x² + 120x – 160x - 9600 = 0

2x (x - 60) - 160 (x -60 ) = 0

(2x – 160) (x - 60) = 0

2x - 160 = 0

x = 80

x - 60 = 0

x = 60

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )