In triangle abc if ae, bf, and cd are the medians and ae and bf intersect at the point (2,3) at what point does cd intersect ae? a. (-2, -3) b. (2, 2) c. (0, 0) d. (2, 3) e. (0, 3)

D:(2,3)

Step-by-step explanation:

We are given that a triangle ABC .If AE,BF and CD are the medians .

We are given that median AE and BF intersect at the point (2,3).

We have to find that at which point CD intersect AE.

From figure, we can see that all three medians AE,BF and CD are intersect at the same point.

If AE and BF intersect at (2,3).Then CD is also intersect AE at point (2,3).

Therefore, option D is true.

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.