Suppose that 85% of all business managers are willing to switch companies if offered a salary increase of 20%. If a headhunter randomly contacts a simple random sample of 51 managers, what is the probability that the proportion willing to switch companies if offered a higher salary is between 0.9115 and 0.946? (Choose the best/closest answer to account for minor rounding)

Hint: For maximum accuracy, you should use technology rather than the Normal Tables to compute this probability.

.8633
.0345
.6900
.0819
.0742

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!

I'm not sure sorry that i couldn't