The height of a triangle is 6x cm and the base is (3x + 10) cm. The area of the triangle is 816 cm. What are the dimensions of the base and height of the triangle?

Height: 48 cm

Base: 34 cm

Step-by-step explanation:

Area = ½ × base × height

816 = ½ × (3x + 10) × (6x)

1632 = 18x² + 60x

3x² + 10x - 272 = 0

3x² + 34x - 24x - 272 = 0

x(3x + 34) - 8(3x + 34) = 0

(3x + 34)(x - 8) = 0

x = -34/3, 8

x = 8

Dimensions:

6x = 6(8) = 48

3x + 10 = 3(8) + 10 = 34

height = 48cm

Base =  34cm

Step-by-step explanation:

The area of a triangle is found by

A = 1/2 bh  where b is the base and h is the height

A = 1/2 (3x+10) 6x

   = 1/2*3x (3x+10)

   = 3x*(3x+10)

   Distribute

   = 9x^2 +30x

The area of a triangle is 816

816 = 9x^2 +30x

Subtract 816 from each side

816-816 = 9x^2 +30x-816

0 = 9x^2 +30x-816

Factor out a 3

0 = 3(3x^2 +10x -272)

Factor

0=3( 3x +34) (x-8)  

Using the zero product property

3x+34 =0    x-8 =0

3x = -34           x=8

x = -34/3         x=8

Since we cannot have a negative length

x=8

height = 6x = 6*8 = 48

Base = 3x+10 = 3*8+10 = 34

the f

last graph i believe

step-by-step explanation:

worked it out i believe