A rolling pin has two identical cylindrical handles attached to a larger handle that is 12 inches long. The large cylinder measures 5 inches in diameter and the handles measure 1.5 inches in diameter. What is the volume of the rolling pin in cubic inches? Round to the nearest tenth

Volume of the rolling pin =  246.09  

Step-by-step explanation:

Length of larger cylinder L = 12 in

Diameter of larger cylinder D = 5 in

Diameter of two handles = 1.5 in

Length of two handles = 3 in

Volume of the rolling pin = Volume of two handles + Volume of larger cylinder

Volume of two handles = 2 ()

Volume of two handles =  2 (3.14 × × 3 )

Volume of two handles = 10.59  

Volume of larger cylinder = ()

Volume of larger cylinder = (3.14 × × 12 )

Volume of larger cylinder = 235.5  

Volume of the rolling pin =  10.59 + 235.5

Volume of the rolling pin =  246.09  

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thus there are 1 · c(9,4) ways, or, if we calculate it,

thus there are 126 ways to form such "words."

answer: 0.11 cents for each egg

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you have to divide 1.35 / 12 = 0.1125