The population of Marshville is loosing 20% of their population of frogs per year. There are currently 900 frogs in Marshville. How many frogs will there be in 5 years?

There will be 262 frogs in 5 years

Step-by-step explanation:

The population of Marshville can be modeled by the following equation.

In which P(t) is the population after t years, P(0) is the initial population, and r is how much the population decreases by year.

In this problem, we have that:

So

How many frogs will there be in 5 years?

This is P(5)

There will be 262 frogs in 5 years

295 frogs

Step-by-step explanation:

The Population of Marshville is loosing 20% of their population of frogs per year.

This means the value of the next year is 80% of the previous year.

This is an example of a geometric series in which the common ratio =80%

The nth term of a geometric series is given as:

Where a=First Term, r=Common Ratio, n=Number of Terms

In this case.

a=900, r=80%=0.8, n=6 (After 5 years)

In 5 years time, there will be 295 frogs in Marshville.

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )

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