Find the equation of a line that is PERPENDICULAR to y = 1/3 x -2 & passes through the point ( 3, 2 ). (CHECK PIC FOR ANSWER CHOICES)

The answer to your question is the letter b)    y = -3x + 11

Step-by-step explanation:

Data

Original line  y = 1/3x - 2

Point = (3, 2)

New line = ? (perpendicular)

Process

1.- Get the slope of the original line

The slope is the coefficient of the x in the line equation.

       y = 1/3x - 2

       slope = m = 1/3

2.- Find the slope of the new line

       new slope = -3  (because the lines are perpendicular)

3.- Find the equation of the new line

         y - y1 = m(x - x1)

 x1 = 3    y1 = 2

-Substitution

        y - 2 = -3(x - 3)

-Simplification

        y - 2 = -3x + 9

        y = -3x + 9 + 2

-Result

       y = -3x + 11

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.