Find the area under the graph of f(x) = e^-2ln(x) on the interval [1, 2].

The rule of e power ln(x) show us that you can replace e and lnx with 1 so the equation will be f(x)=x^2 , take the integral of it it will be x^3 over 3 , put 1 then put 2 and you will get 1/3-(8/3) = the area is -7/8 i hope you understood