You wish to compute the 99% confidence interval for the population proportion. How large a sample should you draw to ensure that the sample proportion does not deviate from the population proportion by more than 0.13?

We need a sample of at least 99

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

The margin of error of the interval is given by:

99% confidence level

So , z is the value of Z that has a pvalue of , so .

How large a sample should you draw to ensure that the sample proportion does not deviate from the population proportion by more than 0.13?

We don't know the proportion, so we use . So we need a sample of size at least n, in which n is found when . So

Rouding up

We need a sample of at least 99

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

they would have to work 32 hours.