A combination lock uses 4 numbers, each of which can be to 29. If there are no restrictions on the numbers, how many possible combinations are available?

810,000

Step-by-step explanation: Thinking of the choosing of one of the numbers in the code as an individual event, we know that there is 30 possibilities per choosing.

Using the Fundamental Counting Principle(look it up if u dont know what it is), we can simply do 30^4 for the 4 digits, getting us 810000

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)