Use the six side-by-side boxplots of on-time graduation rates that you produced to match descriptions to colleges. You may use a college more than once. a. [Choose ] This college is arguably the worst because it has one of the lowest median and the least consistent graduate rates over time. b. [Choose] This college is arguably the best because it has the highest median with fairly consistent graduate rates over time. c. [Choose This college has one of the highest median graduation rates and the best consistency in graduation rates over time. d. [Choose] This college had the highest graduation rate one year but very inconsistent performance over time with the second largest IQR and range. e. [Choose] This college has the lowest median graduation rate and fairly consistent low performance in its typical years .

Answers and Step-by-step explanations:

a)

According to the question, the college that has one of the lowest medians and least consistence in the graduation rates is defined as worst college.

From the provided side by side boxplots, college A has one of the lowest medians. Moreover, the difference between the first and third quartile is much higher than the other colleges. That is, IQR is high for this college. Therefore, there is least consistence in graduation rate.

Hence, the correct answer choice is 'A'

b)

According to the question, the college that has highest median and fair consistence in the graduation rates is defined as best college.

From the provided side by side boxplots ,college D has the highest median. Moreover, the difference between the first quartile and the median is same as the difference between the first quartile and the median. Therefore, there is a fair consistence in graduation rate.

Hence, the correct answer choice is D.

c)

According to the question, the college  has the the lowest median and best consistence in graduation rates.

From the provided side by side boxplots ,college B has the lowest median. Moreover, the difference between the first and third quartile is much lower than the other colleges. That is, IQR is low for this college. Therefore, there is a least consistence in graduation rate.

Hence, the correct answer choice is B.

d)

According to the question, the college has the highest graduation rates in one year and inconsistent graduation rates over years and has second largest IQR and range.

From the provided side by side boxplots ,college F has the highest median. Moreover, the graduation rate of other year not form a proper boxplot due to inconsistence in the graduation rate. Therefore, there is an inconsistence in graduation rate.

Hence, the correct answer is F

e)

According to the question, the college has the lowest median and fairly consistent low graduation rates.

From the provided side by side boxplots, college E has the lowest median. Moreover, the difference between the first and third quartile is higher than college B and D. That is, IQR is higher than college B and D. The graduation rate for all the years is low as compared to other colleges. Therefore, there is a fairly consistent low graduation rate.

Hence, the correct answer choice is E

whats the

step-by-step explanation:

we are given a graph for system of inequalities.

in order to write the system of inequalities for the given graph, we need to find the inequality for each of the line separately.

let us find the slope of dotted line first.

taking two coordinates on the graph.

let us say (0,0) and (3,1).

let us find the slope of the line now.

slope of the dotted line would be =.

y-intercept of dotted line is y=0 only.

plugging slope m= and b=0 in slope-intercept form y=mx+b, we get

.

the line is shaded up of that dotted line.

therefore, for shading up we would take greater than inequality symbol > .

and because it's a dotted line we would take only > symbol in place of = sign in above equation of line.

therefore, inequality for dotted line would be

let us take two points (3,1) and (0,4) on the solid line.

slope of the solid line would be =.

for the solid line we have y-intercept b= 4.

plugging slope m= -1 and b=4 in slope-intercept form y=mx+b, we get

y = -1x + 4.

the line is shaded down of that solid line.

therefore, for shading down we would take less than inequality symbol < .

and because it's a solid line we would take ≤ symbol in place of = sign in above equation of line.

therefore, inequality for solid line would be