A statistics teacher believes that the final exam grades for her class have a normal distribution with a mean of 82 and a standard deviation of 8. Answer the following: if x represents a possible test score for this population, find P(x >92)

P(x >92) = 0.1056

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

P(x >92)

This is 1 subtracted by the pvalue of Z when X = 92. So

has a pvalue of 0.8944

1 - 0.8944 = 0.1056

P(x >92) = 0.1056

50 min

step-by-step explanation:

they will be decreasing both their times in half

60 / 2 = 30

40/2 = 20

30 + 20 = 50

i think the answer is fried chicken ; >

step-by-step explanation: