The difference between two numbers is 28. The larger number is 8 less than twice the smaller number. Find both numbers. [Only an algebraic solution can receive full credit.]

The larger number is 64 and the smaller number is 36.

Step-by-step explanation:

Set up an equation to find the value of one number, x, and use that find find the value of the second number. Use x as the variable for the smaller number. The larger number is 2 times the smaller number minus 8, so the part of the equation for the larger number would be 2x-8. Then because the difference between the two numbers is 28, you would subtract the smaller number, x, from the larger number equation.

The equation should look like this: 2x-8-x=28

Combine like terms to get this: x-8=28

Add 8 to both sides of the equation: x=36

Because x represents the smaller number, the smaller number is 36. To find the larger number, just plug the numbers into the large number equation from earlier: 2(36)-8   The answer for the large number is 64, and the difference between 64 and 36 is 28, proving the answer correct.

the answer is simply just 6n add the two together as they have an n

24 units

step-by-step explanation: